Here is a probability distribution with one missing value. Determine what that value should be.
| Category | A | B | C | D | E | F |
|---|---|---|---|---|---|---|
| Probability | 0.08 | 0.16 | 0.22 | 0.34 | 0.18 | x |
All probabilities have to add up to 1. So, \(\begin{align*} 0.08+0.16+0.22+0.34+0.18+x &= 1 \\ 0.98+x &= 1 \\ x &= 1 - 0.98 \\ x &= 0.02 \end{align*}\)
So, \(P(F) = 0.02\).