PHYS 1130 - Introduction to Meteorology

1.6 Pressure

PHYS 1130 - Introduction to Meteorology
Chapter 1. Earth and Its Atmosphere

Reading

Instruction

\[Weight=mass*(acceleration~of~gravity)=m\cdot 9.8 \qquad Pressure=\frac{Weight}{Area}\]

Example:

A large box has a mass of 2,300 kg. The bottom face of the box has an area of 3.4 \(m^3\). What is the pressure it exerts on the bed of a truck?

Additional Resources

Review Questions

  1. What is the pressure on the feet of a person with a mass of 90 kg and a total surface area on the feet of 0.062 \(m^2\) (that’s 96.1 \(in^2\))?
    • After solving on your own, check the
  2. In the example problem earlier, we saw a shipping box exerts a pressure of 6,629 Pa. What is this pressure in psi? What is this pressure in mb?
    • After solving on your own, check the
  3. Atmospheric pressure is 101,325 Pa. The Earth has a surface area of 196.9 million \(mi^2\) (\(1~mi^2 = 2,590,000~m^2\)). What is the weight of the atmosphere?
    • After solving on your own, check the
## Question 1.6.1 1. What is the pressure on the feet of a person with a mass of 90 *kg* and a total surface area on the feet of 0.062 $$m^2$$? $$Weight = m\cdot 9.8 = 90~kg\cdot 9.8 = 882~N$$ $$Pressure = \frac{Weight}{Area} = \frac{882~N}{0.062~m^2} = 14,226~Pa$$
## Question 1.6.2 2. In the example problem earlier, we saw a shipping box exerts a pressure of 6,629 *Pa*. What is this pressure in *psi*? What is this pressure in *mb*? To convert units: 1. Find an equality between current and desired units 2. Multiply current number by the part of equality with desired unit, divide by other part with current unit $$6,629~Pa\cdot\frac{14.7~psi}{101,325~Pa} = 6,629\frac{14.7~psi}{101,325} = 0.962~psi$$ So that is a weight of 0.962 pounds (lbs) by every square inch of the shipping box. $$6,629~Pa\cdot\frac{1013.25~mb}{101,325~Pa} = 66.29~mb$$
## Question 1.6.3 3. Atmospheric pressure is 101,325 *Pa*. The Earth has a surface area of 196.9 million $$mi^2$$ ($$1~mi^2 = 2,590,000~m^2$$). What is the weight of the atmosphere? $$Area = 196,900,000~mi^2\cdot\frac{2,590,000~m^2}{1~mi^2} = 510,000,000,000,000~m^2$$ $$Pressure = \frac{Weight}{Area} \qquad\to\qquad Weight = Pressure\cdot Area$$ $$Pressure = 101,325~Pa \cdot 510,000,000,000,000~m^2 = 51,700,000,000,000,000,000~N$$ (Your calculator likely says 5.17E19. That is 5.17 * 10,000,000,000,000,000,000 (that's 19 0's).) That is 51.7 quintillion Newtons, or 11.24 quintillion pounds, or 5.62 quadrillion tons! Our atmosphere is really heavy!